Mathematics
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OpenStudy (anonymous):
what is the product in simplest form? state any restrictions. x^2+7x+10/x+3 times x^2-3x-18/x^2+x-2
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OpenStudy (gorv):
\[x \neq -3\]
OpenStudy (anonymous):
?does that mean the answer is -3?
OpenStudy (gorv):
\[x^2+x-2 \neq 0\]
OpenStudy (anonymous):
what?
OpenStudy (gorv):
no no it is just restriction
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OpenStudy (gorv):
denominator should not be zero otherwise we will get infinity as ans
OpenStudy (anonymous):
im so confused you have to understand i have no clue what im doing.....im a bit of a dunce when it comes to mathematics.
OpenStudy (gorv):
jst a min
OpenStudy (gorv):
x^2+x-2=0
x^2+2x-x-2=0
x(x+2)-1(x+2)=0
(x-1)(x+2)=0
OpenStudy (gorv):
\[x \neq 1\]
\[x \neq -2\]
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OpenStudy (gorv):
our ans should not be infinity
OpenStudy (gorv):
if denominator equals to zero
than numerator/zero=infinity
so we need to avoid those values which makes denominator zero
OpenStudy (gorv):
@kitty_love
OpenStudy (anonymous):
sooo -1?
OpenStudy (gorv):
at x=1
x=-2 and x=-3
denominator equals to zero
so avoid these three value
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OpenStudy (anonymous):
ok so the restrictions are 1,-2,and 3?
OpenStudy (gorv):
x^2+7x+10= (x+5)(x+2) on factoring
x^2-3x-18=(x-6)(x+3) on factoring
OpenStudy (gorv):
yeah and that is -3 not 3
OpenStudy (anonymous):
? so which is it?
OpenStudy (gorv):
wait i m solving
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OpenStudy (gorv):
\[\frac{ (x+5)*(x-6) }{ x-2 }\]
OpenStudy (gorv):
this is ur final ans
OpenStudy (anonymous):
thank you so much. and thanks for being pationant.