Question

Sin^-1(sin 4pi/7)
Ive been on this for the past 30 mins. I just cant understand it

Answer 1

here is an example for u
\[\sin \frac{ \pi }{ 6 } = \frac{ 1 }{ 2 }\]
then
\[\sin^{-1} \frac{ 1 }{ 2 } = \frac{ \pi }{ 6 }\]
now multiply both sides by (sin)
\[\sin [\sin^{-1} \frac{ 1 }{ 2 } ] = \sin \frac{ \pi }{ 6 }\]
but
\[\sin \frac{ \pi }{ 6 } = \frac{ 1 }{ 2 }\]
there for
\[\sin [\sin^{-1} \frac{ 1 }{ 2 } ] = \ \frac{ \ 1 }{ 2 }\]

did u get it ?

Answer 2

I understand the concept, but i dont understand what sin\[\frac{ 4\pi }{ 7 }\] is equal to

Answer 3

How do you find that out?

Answer 4

u want to find sin (4pi/7) ?

Answer 5

Yup.