Question

l

Answer 1

do you still need help?

Answer 2

Yes I do! Thanks. @Lena772

Answer 3

well the area is

\[A = \frac{3a + 9}{2a - 6} \times \frac{4a+4}{a + 3}\]

next step needs to be factoring the fractions

\[\frac{3(x + 3) \times 2(x + 2)}{2(x -3)\times(x + 3)}\]

now remove the common factors...

whats left is the answer...

the restriction will be the value of a that makes the denominator zero

Answer 4

oops sorry fro changing from a to x...

the simplified form should have a rather than x

Answer 5

So would it be x +2/x + 3?

Answer 6

well not quite as (a +3) is a common factor...

so the common factors are 2 and (a + 3)

which leaves

\[A = \frac{3(a + 2)}{(a - 3)}\]

to find the restriction solve

a - 3 = 0

Answer 7

and a must equal 3 since 3 - 3 = 0. Alrighty..makes since now. Thanks!