Question

at the beginning of the bake sale, mary set aside 4 pies for herself. karen then bought half of the remaining pies for her birthday party, and 5 more pies were sold during the sale. when the sale was over there was 16 pies remaining.
how many pies were there before the bake sale started?

Answer 1

@johnweldon1993 can you help me please :) it has been a long time since I have done this

Answer 2

I'll give you a medal for helping someone please :)

Answer 3

@jdoe0001

Answer 4

I believe it should be 50

Answer 5

the original amount they had was "x"
we know they sold 4 to Mary, then after they sold that to Mary, they're left with " x -4 "

then Karen came in and bought half that, that is \(\bf \cfrac{x-4}{2}\)

and after that, 5 more pies were sold

so let's see how many they sold \(\bf (x-4)+\cfrac{x-4}{2}+5\)

they had 16 pies leftover
so we could say that the total amount of pies is \(\bf (x-4)+\cfrac{x-4}{2}+5+{\color{red}{ 16}}\) and that should equals "x"

solve for "x"

Answer 6

sorry 46, add 5 to 16=21 double that 42 add the pies that were set aside + 4 = 46

Answer 7

hmme lemme recheck myself

Answer 8

is 46 one of the answers? @vshiroky

Answer 9

It doesn't give options

Answer 10

I think it should be instead just 4 for Mary

Answer 11

It was 46. Thank you :)

Answer 12

\(\bf 4+\cfrac{x-4}{2}+5+{\color{red}{ 16}}=x\)

keep in mind that when Mary bought 4 from the total "x", she left only x-4
and Karen got half that, that is \(\bf \cfrac{x-4}{2}\)

Answer 13

it should be 46, because there were 16 pies remaining, someone bought 5 pies, 5+16=21 someone bought half the remaining pies after the 4 were set aside 21x2=42 4 pies were set aside 42+4=46

Answer 14

ya np @vshiroky