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Suppose a car begins at 100 kph, but decelerates at a rate of 20 km/h^2. Write a definite integral to represent the car's displacement during the first 4.5 hours and evaluate geometrically.
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$$ u=100~kph\\ v=\cfrac{dx}{dt}\\ a=\cfrac{dv}{dt}\\ $$ If s is displacement, t is the time, u in initial velocity and a is acceleration, we get the following upon integrating the previous: $$ s=ut+\cfrac{1}{2}at^2 $$ The question is asking you to get from the 1st set of equations to the displacement equation (i.e. s) Geometrically, I would just draw an graph with distance (s) on the y axis and time (t) on the x axis, using the final equation.
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