HELP PLEASE!! if the slope of a line through the origin and (-2, b) is 2, and the line through (b, -2) and (a, 5) is parallel to that line, what is the value of a?
do you understand what you have?
@nincompoop i dont really know how to start the problem
do you know the slope-intercept form of a line?
@nincompoop yes y2-y1over x2-x1
NO
that is the formula to solve for the slope given two points but you were given the slope already, it says 2
oh wait y=mx+b? @nincompoop
yes
do you know that equation's parts?
so use plug in the y-value into the equation?
do you have the y value?
well in the question it just says the line through (b, -2) and (a, 5) are parallel to the line that goes through the origin and (-2, b).....just look at the original problem if that sounded confusing
@nincompoop
I am not confused
so how would you plug in the values?
would i use point slope formula? @nincompoop
try if it works
@nincompoop it didnt work for me lol or maybe im doing something wrong
@KinzaN could you help me please?
Okay, so you're given two points on a line and its slope: "through the origin" = (0, 0) and point (-2, b), with slope (m) = 2 Using this information, you can find "b." (0, 0) -> (x1, y1) (-2, b) -> (x2, y2) m = 2
Using this value of "b" which you should be able to solve, repeat the process for the second set of data: (b, -2) -> (x1, y1) (a, 5) -> (x2, y2) Is this line is "parallel," its slope is the same: m = 2.
Et j'ai fini.
remember that y-intercept is when x = 0 (0, y) and x-intercept is when y = 0 (x, 0)
"i am not confused" i love nin
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