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If you need 60 000 codes, how many digits long should each code be? There should be no repeated digits!
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We want 60,000 n-digit numbers with no repeated digits. Assuming that the code may begin with zero, there are 10 choices for the first digit, 9 choices for the second digit, 8 choices for the third digit, etc. We find that 10\times9\times8\times7\times6 = 30,240 . . . That is, there are only 30,240 five-digit codes. We must use six-digit codes with 10\times9\times8\times7\times6\times5 = 157,200 permutat
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