Mathematics
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OpenStudy (anonymous):
Help please!!!
Simplify the following expression
x-4y+5z-3x-y+2z
a. -2x-5y-7z
b.-2x-5y+7z
c.-2z+5y-3z
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OpenStudy (cggurumanjunath):
group all the x ,y and z terms .
OpenStudy (cggurumanjunath):
(x-3x) + (-4y-y) + (5z+2z)
OpenStudy (cggurumanjunath):
x(1-3)+y(-4-1)+z(5+2)
OpenStudy (cggurumanjunath):
is it clear ? @Coralgirl
OpenStudy (anonymous):
not quite but I am trying to understand it
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OpenStudy (anonymous):
\(x-4y+5z-3x-y+2z=-2x-5y+7z\)
OpenStudy (anonymous):
\(x\)=apple
apple-3apple=-2apple
OpenStudy (anonymous):
y=orange
-4orange-orange=-5orange
OpenStudy (anonymous):
z=banana
5banana+2banana=7banana
OpenStudy (anonymous):
okay how to do you arrange it @AntarAzri ?
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OpenStudy (anonymous):
how to do you rearranged them to solve ?
OpenStudy (anonymous):
-2apple-5orange+7banana
and apple x, orange y, banana z
OpenStudy (anonymous):
What do you mean by arranging ?
OpenStudy (anonymous):
is it like -y-4y +5z+2z+3x-x
OpenStudy (anonymous):
Not like but it is
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OpenStudy (anonymous):
btw, you must begin by apple, orange, then banana
OpenStudy (anonymous):
Okay ?
OpenStudy (anonymous):
-4y-y-3x-x+5z+2z?
OpenStudy (anonymous):
Well, you want one x one y and one z, right ?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
then, do the sum of your \(x\)s \(y\)s and \(z\)s
OpenStudy (anonymous):
x-3x = -2x
OpenStudy (anonymous):
Awsome
OpenStudy (anonymous):
What about y
OpenStudy (anonymous):
Come on do the sum
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OpenStudy (anonymous):
-4y-y ?
OpenStudy (anonymous):
5y
OpenStudy (anonymous):
it's kinda \(y(-4-1)=?\)
OpenStudy (anonymous):
How much is \(-4-1=?\)
OpenStudy (anonymous):
last one is 7z
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OpenStudy (anonymous):
Nope, you must get y first
OpenStudy (anonymous):
3
OpenStudy (anonymous):
sorry i mean \(4+1\) ?
OpenStudy (anonymous):
5
OpenStudy (anonymous):
that's right, \(-4y-y=-y(4+1)\) and that equal to what ?
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OpenStudy (anonymous):
0kay
OpenStudy (anonymous):
Equal to what ?
OpenStudy (anonymous):
5y
OpenStudy (anonymous):
\((4+1)\) times \(-y\) ?
OpenStudy (anonymous):
\(4+1\) is \(5\) and \(-y\) that give us \(-5y\), right ?
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OpenStudy (anonymous):
yes sorry
OpenStudy (anonymous):
Did you studied the negative numbers ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I am not getting this picture quite well. its kind of messy
OpenStudy (anonymous):
You come down \(4\) times from \(0\) which \(-4y\) and you come down again one more time which is \(-(1)y\) and you will be in the -5 degree, right
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OpenStudy (anonymous):
Yup it's messy sorry
OpenStudy (anonymous):
yes, course
OpenStudy (anonymous):
no problem at all, I got it
OpenStudy (anonymous):
|dw:1392388553751:dw|
OpenStudy (anonymous):
Think of it that way
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OpenStudy (anonymous):
Well, what if you come down 6 times and than 7 times where you will be ?
OpenStudy (anonymous):
-6, -7
OpenStudy (anonymous):
Yup the sum I mean ?
OpenStudy (anonymous):
Consider your self siting in \(0\) than you come down 6 times than 7 times again where you will be ?
OpenStudy (anonymous):
I mean you are siting on line :D
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OpenStudy (anonymous):
-2
OpenStudy (anonymous):
-5
OpenStudy (anonymous):
(SITTING)
OpenStudy (anonymous):
Nope
OpenStudy (anonymous):
-1
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OpenStudy (anonymous):
-2
OpenStudy (anonymous):
-3
OpenStudy (anonymous):
-4
OpenStudy (anonymous):
-5
OpenStudy (anonymous):
-6
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OpenStudy (anonymous):
-7
OpenStudy (anonymous):
|dw:1392388918270:dw|
OpenStudy (anonymous):
Right you are in the (-7)
OpenStudy (anonymous):
7
OpenStudy (anonymous):
Sorry, I'm wrong, could you start from -6 and you come down 7 times ?
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OpenStudy (anonymous):
Where you will be ?
OpenStudy (anonymous):
-7
OpenStudy (anonymous):
sorry -12
OpenStudy (anonymous):
Wrong, let me explain again
OpenStudy (anonymous):
sorry for trouble :(
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OpenStudy (anonymous):
Are you sure -12 ?
OpenStudy (anonymous):
no i am not sure
OpenStudy (anonymous):
Isn't -13 ?
OpenStudy (anonymous):
Oh yea, i made mistake on counting