can someone help me with coefficients pleeeaaassseee
Perhaps if you post an actual problem...
okay jst a sec
7(6-x)
What are you supposed to do?
sorry Use the distributive property to remove the parentheses.
there are a lot that i have to do can you help with all of them? please
Okay. Distributive property says \[a(b-c) = a*b - a*c\]What does that tell us about your problem?
i hav no idea i suc at mth
spelling, too, it appears!
42-7x
ha ha lol i am very good at English i just choose to write this way
Let's write your expression and mine right over each other: \[7(6-x)\]\[a(b-c)\] What corresponds to \(a\)? What corresponds to \(b\)? What corresponds to \(c\)?
a correspondes to b and b to c i think
No, match up \(a\) with something from your expression. Here are your choices: \(7\), \(6\), \(x\)
7 with A 6 with B and x with C
Very good. Now let's look at my distributive property formula again: \[a(b-c) = a*b - a*c\]You know what \(a\),\(b\), and \(c\) are in your expression. Fill in the blanks here.
is this right? 7(6-x)=7x6-7x
So far so good. Better to use something like * (probably shift-8 on your keyboard) to show multiplication. What is 7*6?
42
that is right and i found the multiplication sign on my keyboard * haha
so \[7(6-x) = \]
so sorry my PC timed out and lost the problem
but cn u hlp wth a nothr 1
no, you answer this one first. \[7(6-x) = \]
\[a(b-c) = a*b - a*c\]\[7(6-x) = \]
42-7x
Very good. Okay, what's the other problem?
(w+9)7
Okay, we know that order doesn't matter for multiplication, so we can write that as \[7(w+9)\]And in case it isn't intuitively obvious, that same distribution property we used before works here, too: \[a(b+c) = a*b + a*c\] \[(w+9)7 = 7(w+9) = \]
what does w equal
hello?
hello???
Hello!!!!!!!!!!
\(w = w\) — it doesn't matter what value it has. Follow the pattern. \[7(w+9)\]\[a(b+c)\] \[a(b+c) = a*b + a*c\]\[7(w+9) = \]
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