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Mathematics 15 Online
OpenStudy (anonymous):

can someone help me with coefficients pleeeaaassseee

OpenStudy (whpalmer4):

Perhaps if you post an actual problem...

OpenStudy (anonymous):

okay jst a sec

OpenStudy (anonymous):

7(6-x)

OpenStudy (whpalmer4):

What are you supposed to do?

OpenStudy (anonymous):

sorry Use the distributive property to remove the parentheses.

OpenStudy (anonymous):

there are a lot that i have to do can you help with all of them? please

OpenStudy (whpalmer4):

Okay. Distributive property says \[a(b-c) = a*b - a*c\]What does that tell us about your problem?

OpenStudy (anonymous):

i hav no idea i suc at mth

OpenStudy (whpalmer4):

spelling, too, it appears!

OpenStudy (anonymous):

42-7x

OpenStudy (anonymous):

ha ha lol i am very good at English i just choose to write this way

OpenStudy (whpalmer4):

Let's write your expression and mine right over each other: \[7(6-x)\]\[a(b-c)\] What corresponds to \(a\)? What corresponds to \(b\)? What corresponds to \(c\)?

OpenStudy (anonymous):

a correspondes to b and b to c i think

OpenStudy (whpalmer4):

No, match up \(a\) with something from your expression. Here are your choices: \(7\), \(6\), \(x\)

OpenStudy (anonymous):

7 with A 6 with B and x with C

OpenStudy (whpalmer4):

Very good. Now let's look at my distributive property formula again: \[a(b-c) = a*b - a*c\]You know what \(a\),\(b\), and \(c\) are in your expression. Fill in the blanks here.

OpenStudy (anonymous):

is this right? 7(6-x)=7x6-7x

OpenStudy (whpalmer4):

So far so good. Better to use something like * (probably shift-8 on your keyboard) to show multiplication. What is 7*6?

OpenStudy (anonymous):

42

OpenStudy (anonymous):

that is right and i found the multiplication sign on my keyboard * haha

OpenStudy (whpalmer4):

so \[7(6-x) = \]

OpenStudy (anonymous):

so sorry my PC timed out and lost the problem

OpenStudy (anonymous):

but cn u hlp wth a nothr 1

OpenStudy (whpalmer4):

no, you answer this one first. \[7(6-x) = \]

OpenStudy (whpalmer4):

\[a(b-c) = a*b - a*c\]\[7(6-x) = \]

OpenStudy (anonymous):

42-7x

OpenStudy (whpalmer4):

Very good. Okay, what's the other problem?

OpenStudy (anonymous):

(w+9)7

OpenStudy (whpalmer4):

Okay, we know that order doesn't matter for multiplication, so we can write that as \[7(w+9)\]And in case it isn't intuitively obvious, that same distribution property we used before works here, too: \[a(b+c) = a*b + a*c\] \[(w+9)7 = 7(w+9) = \]

OpenStudy (anonymous):

what does w equal

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

hello???

OpenStudy (anonymous):

Hello!!!!!!!!!!

OpenStudy (whpalmer4):

\(w = w\) — it doesn't matter what value it has. Follow the pattern. \[7(w+9)\]\[a(b+c)\] \[a(b+c) = a*b + a*c\]\[7(w+9) = \]

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