Would I use cosine, or tangent for this?
From a boat on the lake, the angle of elevation to the top of a cliff is 18°41'. If the base of the cliff is 991 feet from the boat, how high is the cliff (to the nearest foot)?
@jdoe0001
Your not the real batman
Yes, I am. You are a failure. You don't even use proper punctuation.
K no need to get hostile, you call me a failure, yet you are the one asking for help?
Idiot.
This is a such a joke of question as well, probably the dumbest question on OS. If you can't do this, find a new profession.
I was joking. Laugh out loud. And asking for help does not make you a failure. In fact, if no one ever asked for help, we really would all be idiots.
tangent
You got your answer, now close it dummy.
|dw:1392419788488:dw|
I'm 16 years old. Right now, that is my profession. I assumed tangent, but it had just asked me a similar question, so I thought there might be something different about this one. Thank you jdoe! And may God bless you both.
\(\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies adjacent\cdot tan(\theta)=opposite\)
Your rudeness is quite adorable @iambatman ! :3 Sure know how to make a girl smile.
Did you get a negative number @jdoe0001 ?
oh cmon you can at least get the answer yourself
Goodbye @iambatman ! God bless you! I won't be seeking your assistance.
I'm atheist
Then God bless you even more. I'll pray for you! <3
ahemm... nope, it's a positive length, make sure your calculator is in Degrees mode notice you have the angle in degrees
Oops. That makes more sense. Sorry about all that nonsense.
lolol
You're not even close to being batman!
Sweetheart, I feel you are wasting both your time, and mine. Please go help someone else, seeing as you're not helping me in the least. In fact, you're quite annoying. I said I would pray for you, I don't know what else you are seeking. And the reason I love him is because we have similar pasts, not just a random athiest obsession. Enjoy the rest of your day!
ahemm \(\bf \begin{array}{cccllll} degrees&minutes\\ \hline\\ 1&60\\ x&41 \end{array}\implies \cfrac{1}{x}=\cfrac{60}{41}\implies 0.68333 \approx x\\ \quad \\ \quad \\ 18^o41' \approx 18.68333^o\)
Nope. I did it with 18.41 for some reason. It should have been 18.68. So it would be 335.05, right?
yeap
You posted that just as I realized my mistake. Thanks again! :) God bless!
yw
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