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x^5+x=1 solve for x
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find the positive root
Newton's method
not Galileo's ?
uhm can I use Wolfram Alpha? :DD
laughing out loud
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I am trying to figure out an easy way to answer this
by Newton's method i got \[x \approx 0.7548\]
Only one answer?
sure you did by wolfram's method I got x = 0.754877666246693
one real and 4 complex
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teach us, musss
teach us, oh newton incarnatete
let x^5+x-1=f(x) if x=0 f(0)=-1 if x=1 f(1)=1 f(0).f(1)=negative that means we have root in (0,1)
Yep, either newton's method or graphing. You can't solve for x algebraically
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i used numerical method :)
laughing out loud i saw it done algebraically completing the square/quadratic formula working on another one to do this besides newton
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