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Mathematics 21 Online
OpenStudy (nincompoop):

x^5+x=1 solve for x

OpenStudy (nincompoop):

find the positive root

OpenStudy (anonymous):

Newton's method

OpenStudy (nincompoop):

not Galileo's ?

OpenStudy (anonymous):

uhm can I use Wolfram Alpha? :DD

OpenStudy (nincompoop):

laughing out loud

OpenStudy (nincompoop):

I am trying to figure out an easy way to answer this

OpenStudy (anonymous):

by Newton's method i got \[x \approx 0.7548\]

OpenStudy (hba):

Only one answer?

OpenStudy (nincompoop):

sure you did by wolfram's method I got x = 0.754877666246693

OpenStudy (anonymous):

one real and 4 complex

OpenStudy (nincompoop):

teach us, musss

OpenStudy (nincompoop):

teach us, oh newton incarnatete

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Newton%27s_method

OpenStudy (anonymous):

let x^5+x-1=f(x) if x=0 f(0)=-1 if x=1 f(1)=1 f(0).f(1)=negative that means we have root in (0,1)

OpenStudy (anonymous):

Yep, either newton's method or graphing. You can't solve for x algebraically

OpenStudy (anonymous):

i used numerical method :)

OpenStudy (nincompoop):

laughing out loud i saw it done algebraically completing the square/quadratic formula working on another one to do this besides newton

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