if f(x)=1/x-1 what is the average rate of change of f between x and x+h?
I got it down to (1/x-1) - (1) / (x-2) but i'm stuck afterwards
AVERAGE rate of change is just the slope without using limits
=[f(b) - f(a)]/(b-a) or =
or you can try to take the derivative since there will be at least one value when average rate of change = instantaneous rate of change if and only if the equation is continuous
I get the formula, I honestly just have problems solving complex fractions? it's that what it's called?
no
what formula do you get?
the first one f(b)-f(a)/b-a
are you taking calculus?
no... alg/trig
I'll watch it thank you :)
difference quotient (x, f(x)) , (x+h, f(x+h))
any luck?
I sort of get it...but it's not clicking somehow...
what pretty much threw me off is not fact that f(x)=1/x-1 I can solve the other D.Q's that includes a function just fine, somehow not clicking with the fraction.
is the fact*
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