if f(x)=1/x-1 what is the average rate of change of f between x and x+h?

Question

anonymous · Answer

I got it down to (1/x-1) - (1) / (x-2) but i'm stuck afterwards

nincompoop · Answer

AVERAGE rate of change is just the slope without using limits

nincompoop · Answer

=[f(b) - f(a)]/(b-a)

or 

=

nincompoop · Answer

or you can try to take the derivative 
since there will be at least one value when average rate of change  = instantaneous rate of change if and only if the equation is continuous

anonymous · Answer

I get the formula, I honestly just have problems solving complex fractions? it's that what it's called?

nincompoop · Answer

no

nincompoop · Answer

what formula do you get?

anonymous · Answer

the first one f(b)-f(a)/b-a

nincompoop · Answer

are you taking calculus?

anonymous · Answer

no... alg/trig

nincompoop · Answer

http://www.youtube.com/watch?v=kWx6ICMyhWI

anonymous · Answer

I'll watch it thank you :)

nincompoop · Answer

difference quotient 
(x, f(x)) , (x+h, f(x+h))

nincompoop · Answer

any luck?

anonymous · Answer

I sort of get it...but it's not clicking somehow...

anonymous · Answer

what pretty much threw me off is not fact that f(x)=1/x-1 I can solve the other D.Q's that includes a function just fine, somehow not clicking with the fraction.

anonymous · Answer

is the fact*