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x^2-5x=14
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Hi I am willing to help. First we are going to subtract 14 off both sides of the equation. than factor and than we will have to solutions
x^2-5x-14 (x-7)(x+2) our solutions are x=7 and x=-2
rewrite the equation as \[x^2 - 5x - 14 = 0\] this can be solved by factoring find the factors of -14 that add to -5 hint: the larger factor is negative then its (x + factor 1)(x + factor 2) = 0 to find the solutions its then x + factor 1 = 0 and x + factor 2 = 0 hope it helps
\({\bf x^2-5x=14\implies x^2-5x-14=0}\large \qquad \begin{array}{cccl} x^2&-5x&-14&=0\\ &\uparrow &\uparrow \\ &-7+2&-7\cdot +2 \end{array}\)
Thank You so much!
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