Find an equation for the line with the given properties Parallel to the line 5x-y = -10 containing the points (0,0)
Principle: parallel lines have the same slope. Action: Find the slope of the given line 5x-y=-10. I think you mean "containing the point (0,0)," (not points). Use the point-slope formula of a straight line to determine the desired equation. You know the slope of this new line and you know that this line passes through (0,0).
apologies for the typo. Is the formula =y -y1 = m(x-x1)
Yes, that's the point-slope formula. The given point is (0,0). What is the slope of the given line? That's the slope y ou'll want to substitute into the point-slope formula to obtain the eq'n of this new line thru (0,0).
will try that again.
Solve 5x-y = -10 for y. Then compare the result to y=mx+b. Identify the value of the slope, m.
i got x=1/5y - 2
hiya mathmale: i got x=1/5y -2
5x-y=10 can be written as y=5x+10
5x - y = -10 when x = 0 y = 10 when y = 0 5x -0 =-10 so x = -2 now you have points on this line find the slope
parallel lines have the same slope so the slope for the "new" line passing through (0, 0) is 5
eqn of line y = mx + b
right.... got it now thank you. Thanks triciaal.
sorry for my (unintended) absence from this discussion. I was asking you (afievans) to solve the given equation for y (not for x). 5x-y=-10 becomes y=5x+10, which has slope 5.
Then, with slope 5 and point (0,0), the equation of the line thru this point is y-0=5(x-0), or y = 5x.
I'm curious: How come you solved for x when asked to solve for y? Don't want to put you on the spot, but thought it important to ask you about this.
honestly don't know how i got solving for x. guess i am just overwhelmed. maths is not my best subject...lol
Like anything else, maths gets easier with practice!
i know right.... thanks for helping.
Join our real-time social learning platform and learn together with your friends!