A photo is 6 inches long. Kamala enlarged the photo so that it is twelve inches long. By keeping the same proportion of the photo, what would be the width of the photo if the enlarged photo is 8 inches wide? Two images of rectangles. The first is six inches long and ? wide. The second is twelve inches long and eight inches wide Does this relationship represent direct or inverse variation? (1 point) Using the appropriate formula, find k. (1 point) Show your work and calculate the width of the original photo. (2 points)
I need help please. I'm just confused about this.
4 inches for the first one.
idk
2nd one is 16
What?!?! I got the first and second question done with. 1) It is Direct Variation. 2) The proper formula is y = kx and k it 2 I need help on the THIRD question so idk where you got 16 from...
idk sorry
if y is the large photo (width or height) and x is the smaller photo (width or height) you have y = 2x they tell you the large photo is twelve inches long and eight inches wide they want the width of the smaller (original) photo. using what we know: width of the large photo is 8: 8 = 2 x to find x, divide both sides by 2 8/2 = 2/2 x or 4 = x
the width of the large photo is twice the width of the original photo if the width of the large photo is 8, then the width of the original photo is 4 using direct variation, we see that this must be true: y= 2x 8= 2*4
I already figured it out, but thanks @phi !
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