Question

d to the 4th+32=12d squared?
help please

Answer 1

so d to the 4th mean d with exponent 4 ?

Answer 2

yes!

Answer 3

so than just note d^2 = t and will get an quadratic equation in t

hope you can solve it

Answer 4

but dont forget it that t_1 and t_2 you need make equal d^2

Answer 5

t_1 and t_2 mean roots of quadratic equation in t

ok ?

Answer 6

\(\bf d^4+32=12d^2\implies d^4-12d^2+32=0\implies (d^{\color{red}{ 2}})^2-12(d^{\color{red}{2}})+32=0\)

notice, tis just a quadratic

Answer 7

shoot, got truncated... anyhow \(\bf d^4+32=12d^2\implies d^4-12d^2+32=0\\ \quad \\\implies (d^{\color{red}{ 2}})^2-12(d^{\color{red}{2}})+32=0\)