Question

P=80-Q/2　turn the equation around so that Q is a function of P (that is, add q/2 to both sides and subtract p from both, then solve for q).　

Answer 1

\(\bf P=80-\cfrac{Q}{2}\qquad {\color{blue}{ add\quad \cfrac{Q}{2}}}\\ \quad \\
P+\cfrac{Q}{2}=80-\cfrac{Q}{2}+\cfrac{Q}{2}\qquad {\color{blue}{ subtract\quad P}} \\ \quad \\
P+\cfrac{Q}{2}-P=80-\cfrac{Q}{2}+\cfrac{Q}{2}-P\)

Answer 2

Q=160-2P?

Answer 3

@jdoe0001