Question

How do i solve (x+6)^2/3=9?

Answer 1

multiply both sides by 3
(x+6)^2= 27

Answer 2

simplify the square
x^2+12x+36=27

Answer 3

substract 27 from both the sides
x^2+12x+9

Answer 4

use the equation
\[x= (-b \pm \sqrt{b ^{2}-4ac})/2a\]

Answer 5

where
a=1
b=12
c=9

Answer 6

\[(x+6)^2=27\]
\[\sqrt{(x+6)^2}=\pm \sqrt{27}\]
\[x+6=\pm3\sqrt{3}\]

Answer 7

\[x=-6\pm3\sqrt{3}\]

Answer 8

@d3v13 would it be
(x + 6)^(2/3) = 9
(x + 6) = 9^(3/2)
x + 6 = -27 , 27
x = -33 , 21

Answer 9

\[(x+6)^{\frac{2}{3}}=9\]
\[((x+6)^{\frac{2}{3}})^{\frac{3}{2}}=9^{\frac{3}{2}}\]
\[x+6=27\]
\[x=21\]

Answer 10

^is right.
9^(1/2)=3
3^3=27

Answer 11

and the reason behind that is
sqrt(-3^2) is not equal to sqrt(9)