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Mathematics 19 Online
OpenStudy (anonymous):

Write the equation for the graphed function.

OpenStudy (anonymous):

A. f(x)= |x-2| B. f(x)= |x+2| C. f(x)= |x| + 2 D. f(x)= |x| - 2

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

so identify the type of shift

OpenStudy (anonymous):

Do I plug in one of the x values?

OpenStudy (anonymous):

The graph shows that when x=-2, y=0. This rules out the options [C] and [D] since for either, if we substitute x=0, y will be 2 or -2. Right?

OpenStudy (anonymous):

Right.

OpenStudy (anonymous):

is it a shift left, right, up, or down?

OpenStudy (anonymous):

Up...??

OpenStudy (anonymous):

So carry on with the other options [A] and [B] now ...

OpenStudy (anonymous):

Because it is already up.

OpenStudy (anonymous):

no, the vertex didn't go up

OpenStudy (anonymous):

Wait, so plug in..

OpenStudy (anonymous):

What?

OpenStudy (anonymous):

Plug in the value of x=-2 in [A] and in [B] and see what value of f(x) [=y] gives you a Zero. Right?

OpenStudy (anonymous):

Oh.. okay. I'll do that.

OpenStudy (anonymous):

Got it?

OpenStudy (anonymous):

|dw:1392605885797:dw|

OpenStudy (anonymous):

Did I do that right?

OpenStudy (anonymous):

Yes :)

OpenStudy (anonymous):

So you got your answer :)

OpenStudy (anonymous):

Thanks! :)

OpenStudy (anonymous):

Cool. Signing off now. Have a good day.

OpenStudy (anonymous):

Yes! I got a 100! Thanks to both of you! :)

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