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limit of n^x/x! as x goes to inf is 0 ,can u explain y?
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Looks like a taylor series expansion.
Did you know \[ e^x = \sum_{n=0}^{\infty }\frac{x^n}{n!} \]
i know the limit of 1/x! will be zero but what about n^x as x-->inf?
Do you know l'hospital's rule?
What you need to realize is that the \(x!\) and the \(n^x\) are both competing.
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yes,u mean Derivation of the numerator and denominator
what the limit of n^x? is that correct ,in this question we have inf/inf so ,we use l'hospital's rule?
We have an indeterminate form \(\infty / \infty\)
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