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Mathematics 9 Online
OpenStudy (anonymous):

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OpenStudy (dls):

Sum of angles of opposite sides in a quadrilateral=?

OpenStudy (dls):

@mathmale ,let him answer my question first

OpenStudy (mathmale):

First, let's review terminology: What's a quadrilateral? I've done an Internet search and have come up with the following: https://www.google.com/search?q=quadrilateral&rlz=1C1CHFX_enUS461US461&oq=quadrilateral&aqs=chrome..69i57j0l5.5293j0j7&sourceid=chrome&espv=210&es_sm=122&ie=UTF-8 Now take a look at the following, to learn something interesting about the sum of the interior angles of a polygon (a quadrilateral is a 4-sided polygon). http://www.mathsisfun.com/geometry/interior-angles-polygons.html I'm not sure this will fully answer your question, but at least it's a start in that direction. Good luck.

OpenStudy (anonymous):

wait so your asking me to tell you the sides? on this problem?

OpenStudy (mathmale):

No. I'm providing you with reference material that may help you to find your own solution. @DLS responded to your question before I did, with a question of his own, so would you please correspond with him and see whether you two can arrive at a satisfactory solution to your homework problem.

OpenStudy (anonymous):

yeah @DLS opposite sides are parallel and opposite angles are equal.

OpenStudy (dls):

If you are correct,then 7x+4=5x-4 x=?

OpenStudy (mathmale):

All you can know from the name "quadrilateral" is that it has four sides. You cannot say that its opposite sides have = lengths. But musa has posted an illustration of a specific quadrilateral which is symmetric about the x-axis, BUT does NOT have opposite sides that are parallel. So plese think up a new description.

OpenStudy (anonymous):

-4?

OpenStudy (dls):

so do u think opposite angles are really equal? can x be -4 ?

OpenStudy (mathmale):

I'll let you two discuss this. Invite me back into the discussion if you need to.

OpenStudy (dls):

The sum of the opposite angles in a cyclic quadrilateral is 180.

OpenStudy (dls):

7x+4+5x-4=180 x=?

OpenStudy (anonymous):

so then no they can't be

OpenStudy (anonymous):

x would equal 15

OpenStudy (dls):

so now your angles are? 7x+4= 5x-4=

OpenStudy (dls):

7(15)+4 is -4/7?!

OpenStudy (anonymous):

oooh never mind it would be 109

OpenStudy (anonymous):

and other would be 71

OpenStudy (anonymous):

and total would equal to 180

OpenStudy (dls):

now sum of all angles in quadrilateral=360 X is given ...solve

OpenStudy (mathmale):

The key to solving this problem is to recognize that the sum of all four interior angles of this figure MUST be 360 degrees. If angle X is 102 degrees, then angle Z is also 102 degrees. Adding 102 and 102 results in what sum? Subtract that sum from 360. The result is the value of (7x+4)+(5x-4). Solve for x!

OpenStudy (dls):

actually u already got x=15

OpenStudy (mathmale):

I'd suggest that you check your result. The sum of the four interior angles of this quadrilateral must be 360 degrees. Therefore, 360 degrees = 102 degrees + 102 degrees + (7x+4) + (5x-4). substitute your x=15 degrees and determine whether or not the above equation is true.

OpenStudy (anonymous):

Got it would be B x would be 13 on here

OpenStudy (mathmale):

Have you checked your answer? Is my equation now true or false?

OpenStudy (anonymous):

yes i did 102+102=204 wy = 156 + 204 =360

OpenStudy (mathmale):

7(13)+4 + 5(13)-4 + 204 = 360 is true. Therefore, x=13 degrees. Congrats!

OpenStudy (anonymous):

yes its true

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