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Sum of angles of opposite sides in a quadrilateral=?
@mathmale ,let him answer my question first
First, let's review terminology: What's a quadrilateral? I've done an Internet search and have come up with the following: https://www.google.com/search?q=quadrilateral&rlz=1C1CHFX_enUS461US461&oq=quadrilateral&aqs=chrome..69i57j0l5.5293j0j7&sourceid=chrome&espv=210&es_sm=122&ie=UTF-8 Now take a look at the following, to learn something interesting about the sum of the interior angles of a polygon (a quadrilateral is a 4-sided polygon). http://www.mathsisfun.com/geometry/interior-angles-polygons.html I'm not sure this will fully answer your question, but at least it's a start in that direction. Good luck.
wait so your asking me to tell you the sides? on this problem?
No. I'm providing you with reference material that may help you to find your own solution. @DLS responded to your question before I did, with a question of his own, so would you please correspond with him and see whether you two can arrive at a satisfactory solution to your homework problem.
yeah @DLS opposite sides are parallel and opposite angles are equal.
If you are correct,then 7x+4=5x-4 x=?
All you can know from the name "quadrilateral" is that it has four sides. You cannot say that its opposite sides have = lengths. But musa has posted an illustration of a specific quadrilateral which is symmetric about the x-axis, BUT does NOT have opposite sides that are parallel. So plese think up a new description.
-4?
so do u think opposite angles are really equal? can x be -4 ?
I'll let you two discuss this. Invite me back into the discussion if you need to.
The sum of the opposite angles in a cyclic quadrilateral is 180.
7x+4+5x-4=180 x=?
so then no they can't be
x would equal 15
so now your angles are? 7x+4= 5x-4=
7(15)+4 is -4/7?!
oooh never mind it would be 109
and other would be 71
and total would equal to 180
now sum of all angles in quadrilateral=360 X is given ...solve
The key to solving this problem is to recognize that the sum of all four interior angles of this figure MUST be 360 degrees. If angle X is 102 degrees, then angle Z is also 102 degrees. Adding 102 and 102 results in what sum? Subtract that sum from 360. The result is the value of (7x+4)+(5x-4). Solve for x!
actually u already got x=15
I'd suggest that you check your result. The sum of the four interior angles of this quadrilateral must be 360 degrees. Therefore, 360 degrees = 102 degrees + 102 degrees + (7x+4) + (5x-4). substitute your x=15 degrees and determine whether or not the above equation is true.
Got it would be B x would be 13 on here
Have you checked your answer? Is my equation now true or false?
yes i did 102+102=204 wy = 156 + 204 =360
7(13)+4 + 5(13)-4 + 204 = 360 is true. Therefore, x=13 degrees. Congrats!
yes its true
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