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Mathematics 15 Online
OpenStudy (anonymous):

Choose the correct graph to fit the equation. 3y = 2x + 3 https://media.glynlyon.com/g_alg02_ccss_2013/3/qi301b.gif https://media.glynlyon.com/g_alg02_ccss_2013/3/qi301c.gif https://media.glynlyon.com/g_alg02_ccss_2013/3/qi301.gif https://media.glynlyon.com/g_alg02_ccss_2013/3/qi302.gif https://media.glynlyon.com/g_alg02_ccss_2013/3/qi303.gif

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

yup?

OpenStudy (anonymous):

do you know how to do this?

OpenStudy (anonymous):

yup hold on

OpenStudy (anonymous):

ok. thanks

OpenStudy (anonymous):

3y = 2x + 3 So, \[y=\frac{ 2x + 3 }{ 3 }\] then start putting some values of x like form about -7 to 7 or any other and calculate the value of y. then make a graph of all the values of x and y. For example (i'll do one for u) let x=1 then \[y=\frac{ 2(1) + 3 }{ 3 } = \frac{ 5 }{ 3 } = 1.666\]

OpenStudy (anonymous):

now calculate others by putting x=-3,-2,-1,0,1,2,3 (that should be enough) and then make a graph

OpenStudy (anonymous):

is it the first graph?

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

this one https://media.glynlyon.com/g_alg02_ccss_2013/3/qi301b.gif

OpenStudy (anonymous):

thanks. Choose the correct graph to fit the equation. 4x - 3y = -1 is this choice 3?

OpenStudy (anonymous):

where are the choises??? same one???

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok let me check

OpenStudy (anonymous):

its this one https://media.glynlyon.com/g_alg02_ccss_2013/3/qi301c.gif

OpenStudy (anonymous):

thanks.

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