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Please help! how do you solve log base4 (2x+1) = log base4 (x+2) - log base4 3
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\[\log_{4} \left( 2x+1 \right)=\log_{4} \left( x+2 \right)-\log_{4} 3=\log_{4} \frac{ x+2 }{ 3 }\] \[2x+1=\frac{ x+2 }{ 3 },solve~ for~ x\]
Do i put 2x +1 over 1 and cross multiply?
correct.
ok im going to do that now thank u!
yw
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i got negative 1/5 as my answer? is that correct @surjithayer
correct.
thanks again!
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