Question

Let \(f: A \rightarrow R\) be defined by \(f(x)=x^3-9x^2+23x-12\), where \(A =[1,3,6]\). Let \(g: B \rightarrow R\) be defined by \(g(x) =x^2-4x+6\) where \(B = [x: \in N : x 6 ] \backslash\) [x: x is an even prime number. Prove that \(f=g\)

Answer 1

by complement definition for B we can see that B = x belonging to natural numbers x l 6.

Answer 2

the fact that x is an even prime number is thrown out the window with that complement definition

Answer 3

so A =[1,4,6] and B must be just 6

Answer 4

so to prove that f=g we need f(6) and g(6)

Answer 5

flub I meant A =[1,3,6]