Question

which is equivalent to 3x/x-7 - x+7/x

a) 2x^2+49/x(x-7)
B)x^2+49/x(x-7)
c)2(x+7)/x(x-7)
d)2(x-7)/x(x-7)

Answer 1

\[\frac{3x}{x-7}-\frac{x+7}{x}\]

Answer 2

Is that the problem?

Answer 3

yes

Answer 4

@Mertsj

Answer 5

You need to write both fractions with the same denominator so:

Answer 6

multiply the first fraction by x/x and

Answer 7

multiply the second fraction by (x-7)/(x-7)

Answer 8

\[\frac{3x}{x-7}\times\frac{x}{x}-\frac{x+7}{x}\times\frac{x-7}{x-7}\]

Answer 9

so you get \[\frac{ 3x ^{2} }{x ^{2-7} }\times \frac{ x ^{2-49} }{x ^{2-7} }\] right?

Answer 10

\[\frac{3x^2}{x(x-7)}-\frac{x^2-49}{x(x-7)}\]

Answer 11

\[\frac{3x^2-x^2+49}{x(x-7)}\]

Answer 12

Collect the like terms.

Answer 13

ok I think I get it so the answer is "a"??