Question

Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that ∠A1 is smaller than ∠A2.)

Answer 1

how do you know when theres a second triangle possible
??

Answer 2

Where is the question?

Answer 3

b = 29, c = 38, ∠B = 25°

Answer 4

It says :satisfy the given condition, But no condition is given.

Answer 5

i just put it : b = 29, c = 38, ∠B = 25°

Answer 6

Do you know the law of sines?

Answer 7

yes : sin A/a=sinB/b=sinC/c

Answer 8

So have you solved for angles C and A and side a?

Answer 9

yes i got C=146.4 and A=8.6 a=10.3

Answer 10

so when it comes down to have this question on the test how would i know that i have to solve for a second triangle?

Answer 11

h<a<b : two triangles where h = height.

Answer 12

a >= b: one triangle
a=h one triangle

Answer 13

i dont get it

Answer 14

You only need to solve for one triangle on your problem.

Answer 15

okay i get it

Answer 16

with the calculations from the first triangle how do i know if a second triangle is possible

Answer 17

Can the height of your triangle be greater than a or b. Not if you have an obtuse triangle. Draw the triangle out and see.