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4p+1>-11 or 6p+3<39 is the compound inequality. Let's simplify these separately. 4p+1>-11 4p+1-1>-11-1 4p>-12 4p/4>-12/4 ***p>-3*** 6p+3<39 6p+3-3<39-3 6p<36 6p/6<36/6 ***p<6*** There must be an open circle on -3 and an open circle on 6. But which directions should the graph point? p<6 indicates that, from the open circle on 6, everything to the left extending forever should be shaded. However, p>-3 indicates that, from the open circle on -3, everything to the right extending forever should be shaded. The two graphs overlap, and we say that the solution is "all reals." This is graphed as choice D.
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