Question

2x^2+3x^2-5 / x+1

Answer 1

factorize 2x^2+3x^2-5 first

Answer 2

Which is (x-1)(x+1), then cancel out x+1

Answer 3

You'll get the answer

Answer 4

No polynomial division

Answer 5

I get it

Answer 6

\[2x^2+3x^2-5 = 5x^2-5 = 5(x^2-1)\]Recognize that \((x^2-1)\) is a difference of squares: \(a^2-b^2 = (a+b)(a-b)\)
with \(a^2=x^2\) and \(b^2=1\) so it can be factored by inspection into \((x+1)(x-1)\) giving us an overall factoring of
\[\frac{5(x+1)(x-1)}{(x+1)}\]Now you can cancel any common factors you see.