Question

you invested of $4000 in two stocks that paid 5% and 7% annual interest. at the end of the year, the totally interest from these investments was $230 . how much was invested at each rate?

Answer 1

@kewlgeek555

Answer 2

@LukeBlueFive

Answer 3

The following two equations can be derived from this word problem:

0.05 * x + 0.07 * y = $230
x + y = $4000

Answer 4

This looks like a substitution problem, so let's separate the variables:

y = $4000 - x

Then substitute this value for y in the first equation, then solve for x:

0.05 * x + 0.07 * ($4000 - x) = $230

Answer 5

This equals:

0.05 * x + $280 - 0.07 * x = $230

Simplifying:

$280 - 0.02 * x = $230

Subtracting $280 from each side:

-0.02 * x = -$50

Writing -0.02 as a fraction:

\[-\frac{2}{100} * x = -$50\]
Simplifying:
\[-\frac{1}{50} * x = -$50\]
Multiply both sides by -50. That will gives you the amount invested in 5% stock. Subtract it from $4000 to get the amount invested in 7% stock.