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What's the question
\[\left( \frac{ 2^{0} }{ 3 } \right)\times \left( \frac{ 1 }{ 3^{-2} }\times5^{0} \right)+\frac{ 3 }{ 5^{0} }\]
We'll anything to the zero power is one. Start there. So (1/3)(1/3^-2)(1)+(3/1)
its 6
Negative exponents need to be moved to the opposite stop. Since it's in the denominator, 3^-2 needs to be moved to the numerator (1/3)(3^2)(1)+3
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Simplify to: (3^2)/3+3 9/3+3 3+3 6
thanks hun
can you help me with another one
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