Use function notation to write the equation of the line. bit.ly/1ffoCNs A. f (x) = 2x – 1 B. f (x) = –2x – 1 C. f (x) = –½x – 1 D. f (x) = –2x + 1
@UnkleRhaukus
f(x)=mx+b where m is the slope, and b is the y-intercept
But, I dont even know what to plug into the unknown variables
look at the plot, what value does the line cross the y-axis? this is the y-intercept b
(0,-1)?
|dw:1392782529451:dw|
So b=-1?
yes
f(x)=mx+(-1)
that is the y-intercept so your almost there
now you just need to get the slope (or gradient )
the gradient is the amount the height changes , when the vertical displacement is positive one unit
or equivalently slope is rise/run between any two points |dw:1392782811761:dw|
i like to choose a run of +1 to make it easy
Ok
m = rise/run = (y_2-y_1)/(x_2-x_1) choose two points, say (x_1, y_1) = (0,-1) and say (x_2, y_2) = (1, -3) (if you want to you can choose any two points)
Ok, I will just use the points you used
Y=2 X=-1?
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