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Mathematics 20 Online
OpenStudy (rane):

How to find the missing/remaining values of a table from spreadsheet ( casio class pad 330) ??????

OpenStudy (rane):

@amistre64 @phi

OpenStudy (amistre64):

ive never worked with a casio class pad so i would not know exactly

OpenStudy (amistre64):

did something or someone corrupt some data in a spreadsheet?

OpenStudy (rane):

no, not that data lol I'm talking abt u know how sometimes we are given a table with only 1 or 2 values, just to get us started on filling out the values of the table spreadsheet, finds those values

OpenStudy (amistre64):

if we are only given 2 values, then the best we can assume is a linear relationship to fit a curve to. but thats all thats going on in my head at the moment. if given enough terms, and if its 'well behaved' then we can usually assess a pattern as well.

OpenStudy (rane):

can i draw out my table here, to help me out ?

OpenStudy (amistre64):

you can give it a shot :)

OpenStudy (rane):

|dw:1392814604268:dw|

OpenStudy (rane):

i have to determine the maximum profit

OpenStudy (amistre64):

looks like we can multiply the first 2 columns to find revenue, and the difference between revenue and profit is expense. to see if there is some consistency about it

OpenStudy (amistre64):

yeah, it looks from the sparse data available that expenses are a constant 5000

OpenStudy (amistre64):

we can determine a relationship now between cost and tickets sold, 3 points form a parabola

OpenStudy (rane):

yh but in order to find the values i have to find any formula

OpenStudy (amistre64):

use the first 2 columns as data points for a quadratic equation: ap^2 + bp + c = sold ; p for price,

OpenStudy (amistre64):

using a matrix to solve the system of equation that is produced is simple enough; not sure how to do it for your calculator tho

OpenStudy (rane):

i know how to do it manually but i just wanted to do it by calc, as well

OpenStudy (amistre64):

find the matrix option and insert the values of p^2 p^1 p^0 and sold (1)^2 (1) (1) (20000) (1.5)^2 (1.5) (1) (17500) (2)^2 (2) (1) (15000) then do an rref operation on it to read off the values for a,b,c of the quadratic

OpenStudy (rane):

thank you

OpenStudy (amistre64):

so i get, number sold = (-5000p + 25000) revenue is just number sold time price: p(-5000p+25000) and profit is revenue minus expenses: p(-5000p+25000) - 5000 and that produces the quadratic i was thinking of

OpenStudy (amistre64):

the vertex gives us the max profit/ticket price ... which is x=5/2, or 2.50

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