How to find the missing/remaining values of a table from spreadsheet ( casio class pad 330) ??????
@amistre64 @phi
ive never worked with a casio class pad so i would not know exactly
did something or someone corrupt some data in a spreadsheet?
no, not that data lol I'm talking abt u know how sometimes we are given a table with only 1 or 2 values, just to get us started on filling out the values of the table spreadsheet, finds those values
if we are only given 2 values, then the best we can assume is a linear relationship to fit a curve to. but thats all thats going on in my head at the moment. if given enough terms, and if its 'well behaved' then we can usually assess a pattern as well.
can i draw out my table here, to help me out ?
you can give it a shot :)
|dw:1392814604268:dw|
i have to determine the maximum profit
looks like we can multiply the first 2 columns to find revenue, and the difference between revenue and profit is expense. to see if there is some consistency about it
yeah, it looks from the sparse data available that expenses are a constant 5000
we can determine a relationship now between cost and tickets sold, 3 points form a parabola
yh but in order to find the values i have to find any formula
use the first 2 columns as data points for a quadratic equation: ap^2 + bp + c = sold ; p for price,
using a matrix to solve the system of equation that is produced is simple enough; not sure how to do it for your calculator tho
i know how to do it manually but i just wanted to do it by calc, as well
find the matrix option and insert the values of p^2 p^1 p^0 and sold (1)^2 (1) (1) (20000) (1.5)^2 (1.5) (1) (17500) (2)^2 (2) (1) (15000) then do an rref operation on it to read off the values for a,b,c of the quadratic
http://www.wolframalpha.com/input/?i=rref%7B%7B%281%29%5E2%2C%281%29%2C%281%29%2C%2820000%29%7D%2C%7B%281.5%29%5E2%2C%281.5%29%2C%281%29%2C%2817500%29%7D%2C%7B%282%29%5E2%2C%282%29%2C%281%29%2C%2815000%29%7D%7D hmm, 0, -5000, 25000 so i guess it was linear :)
thank you
so i get, number sold = (-5000p + 25000) revenue is just number sold time price: p(-5000p+25000) and profit is revenue minus expenses: p(-5000p+25000) - 5000 and that produces the quadratic i was thinking of
the vertex gives us the max profit/ticket price ... which is x=5/2, or 2.50
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