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OpenStudy (anonymous):
How would one solve x^2+5=4x?
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OpenStudy (akashdeepdeb):
x^2 - 4x + 5 = 0 [a=1, b = -4, c = 5] Use the quadratic equation: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] Got it? :)
OpenStudy (anonymous):
Ah, that makes more sense. Thank you very much!
OpenStudy (akashdeepdeb):
:)
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