Question

Consider the following cross:
Parent 1: YyTt
Parent 2: YyTt
Using the rules of probability, determine the probability that the offspring will show YyTT genotype?

A. 1/8

B. 1/16

C. 1/2

Answer 1

so you would use punnet squares to figure this out, correct?

Answer 2

those are all the possible offspring...

Answer 3

on the very top, i have parent one's genes, and on the very left side, i have parent two's genes.

Answer 4

so out of four, you have one that is YyYy, one that is TtTt, and two that are YyTt (TtYy is ths same thing). so 25% YyYy; 25% TtTt; and 50% YyTt