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Mathematics 4 Online
OpenStudy (anonymous):

log2x − 5 25 = 2?

OpenStudy (solomonzelman):

2x-5 is the base, correct ?

OpenStudy (anonymous):

yes

OpenStudy (jdoe0001):

\(\large \bf log_2(x-525)=2\quad ?\)

OpenStudy (solomonzelman):

\[Hint: \color{blue}{ 2= 2 ~ \log_5(5)=\log_5(5^2) =\log_525 }\]

OpenStudy (jdoe0001):

ohh

OpenStudy (solomonzelman):

\[\huge\color{blue}{ \log_{2x-5}25=\log_5 25 }\]

OpenStudy (solomonzelman):

can you solve for x ?

OpenStudy (solomonzelman):

Look at the bases :)

OpenStudy (jdoe0001):

\(\Large{ \bf log_{\color{red}{ a}}{\color{blue}{ b}}=y\implies {\color{red}{ a}}^y={\color{blue}{ b}}\\ \quad \\ \quad \\ log_{{\color{red}{ 2x-5}}}({\color{blue}{ 25}})=2\implies \square ^\square =\square }\)

OpenStudy (anonymous):

can you show me how I have no clue have to do it

OpenStudy (solomonzelman):

\[ \huge\color{blue}{ \log _\color{red} { 2x-5 } 25 } = \huge\color{blue}{ \log _\color{red} {5 } 25 } \] LOOK CLOSER!

OpenStudy (anonymous):

x=5?

OpenStudy (solomonzelman):

Yeah!!!! you got it, pam pa ra ram! :)

OpenStudy (anonymous):

thank you so much

OpenStudy (solomonzelman):

You welcome, np !

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