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Derivatives question:
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I have a baloon of He. It has a r=2m. Then r increases by 1cm. How is the change in volume?
What's stopping you from simply comparing the results? \(\dfrac{4}{3}\pi\;2^{3}\;vs.\;\dfrac{4}{3}\pi\;3^{3}\)
I was wondering the same...
except the second radius won't be 3m...
Oh...I was going to do derivatives...ok..got 40 as answer, thanks :)
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0.4
As a new question, it ask to do the method of diferentiation
So now I take the derivative and get a different answer...by a little...why?
differentials give a linear approximation of the change
what did you get for the second answer?
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