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Quotient rule
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\[g(x) = \frac{ 2e^x+7 }{ 4x^3 }\]
well its u/v \[u = 2e^x + 7..................... v = 4x^3\] and \[u' = 2e^x..........................v' = 12x^2\] the quotient rule says \[\frac{dy}{dx} = \frac{v \times u' - u \times v'}{v^2} \] make the substitutions and simplify
\[\frac{ (4x^3)(2e^2)-(2e^x+7)(12x^2) }{(4x^3)^2 }\]
\[\frac{ 8x^3-24x^2e^x-84x^2 }{ (4x^3)^2 }\] That's what I got, is that correct?
You'll find a very good explanation of the quotient rule here: http://1728.org/chainrul.htm
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I already know the quotient rule. I just needed help with the simplifying
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