Mathematics
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OpenStudy (anonymous):
sin2x = -1 in radians from 0 to 2pie
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Parth (parthkohli):
Hi! Do you know the values for which sine is -1? That would be a start.
OpenStudy (anonymous):
the original equation was sinx cosx = -1/2 and says solve from 0 to 2pie
OpenStudy (anonymous):
After editing I got sin2x=-1
Parth (parthkohli):
that is correct. do you know where sine is -1?
OpenStudy (anonymous):
I don't..
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Parth (parthkohli):
do you know the graph of the sine function?
OpenStudy (anonymous):
nope this is all the information i have to solve
Parth (parthkohli):
hmm. I have idea how to take over.
OpenStudy (anonymous):
A look at the unit circle always helps me in these situations.
Parth (parthkohli):
all right, sin is -1 at 3pi/4 radians and -pi/2 radians
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Parth (parthkohli):
@nagode64 oh yeah... do you know the unit circle?
OpenStudy (anonymous):
3π/4?
OpenStudy (anonymous):
and -π/2 is not in the domain.
Parth (parthkohli):
whoops... i thought -2pi to 2pi. sorry.
Parth (parthkohli):
oh my... sorry 3pi/2. lol
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Parth (parthkohli):
I become really stupid in the presence of someone.
OpenStudy (anonymous):
so the final answer would be 3pi/2 + npi?