Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

sin2x = -1 in radians from 0 to 2pie

Parth (parthkohli):

Hi! Do you know the values for which sine is -1? That would be a start.

OpenStudy (anonymous):

the original equation was sinx cosx = -1/2 and says solve from 0 to 2pie

OpenStudy (anonymous):

After editing I got sin2x=-1

Parth (parthkohli):

that is correct. do you know where sine is -1?

OpenStudy (anonymous):

I don't..

Parth (parthkohli):

do you know the graph of the sine function?

OpenStudy (anonymous):

nope this is all the information i have to solve

Parth (parthkohli):

hmm. I have idea how to take over.

OpenStudy (anonymous):

A look at the unit circle always helps me in these situations.

Parth (parthkohli):

all right, sin is -1 at 3pi/4 radians and -pi/2 radians

Parth (parthkohli):

@nagode64 oh yeah... do you know the unit circle?

OpenStudy (anonymous):

3π/4?

OpenStudy (anonymous):

and -π/2 is not in the domain.

Parth (parthkohli):

whoops... i thought -2pi to 2pi. sorry.

Parth (parthkohli):

oh my... sorry 3pi/2. lol

Parth (parthkohli):

I become really stupid in the presence of someone.

OpenStudy (anonymous):

so the final answer would be 3pi/2 + npi?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!