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Mathematics 19 Online
OpenStudy (anonymous):

What would the second derivative of the graph attached inside look like? Please explain :) thank youu!!

OpenStudy (anonymous):

graph!!

ganeshie8 (ganeshie8):

trick question :)

ganeshie8 (ganeshie8):

since the line is straight, it has a constant slope

OpenStudy (anonymous):

really? how?! :o

ganeshie8 (ganeshie8):

whats the equation of a straight line ?

ganeshie8 (ganeshie8):

y = mx + b right ?

ganeshie8 (ganeshie8):

where, m and b are constants m = slope

OpenStudy (anonymous):

yes:)

ganeshie8 (ganeshie8):

next, whats the relation between 'first derivative' and 'slope' ?

OpenStudy (agent0smith):

what's the derivative of y = c, when c is a constant?

OpenStudy (anonymous):

the first derivative is the slope?

OpenStudy (anonymous):

@agent0smith not sure :/

ganeshie8 (ganeshie8):

yup ! next answering agent's question gives u the final answer !

OpenStudy (agent0smith):

well we know the first derivative of y = mx + b will be... y' = m, right? what's the derivative of y' = m? think if y = 2, what's the derivative? big hint: derivative of a constant is zero.

OpenStudy (anonymous):

yay!! but im not sure how to find that :(

OpenStudy (agent0smith):

er find what...

OpenStudy (anonymous):

oh it posted kinda late haha but i didn't see your explanation! so y=0?

OpenStudy (agent0smith):

y'' = 0, yes (it's second derivative remember)

OpenStudy (anonymous):

ahh yeah y"=0... so would that mean theres no second derivative?

OpenStudy (agent0smith):

^there is. you just wrote it. There's also a third, fourth, fifth... nth derivative. They're all = 0

OpenStudy (anonymous):

ohh hhaa :p awesome! thank you!!

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