http://screencast.com/t/AbLvgSO6Xf

I have worked it out thus far and got e^4x8.
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Not sure how to solve for x when it's an exponent

Question

http://screencast.com/t/AbLvgSO6Xf

I have worked it out thus far and got e^4x>8.
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Not sure how to solve for x when it's an exponent

lyrae · Answer

When does sqrt(1-e^t) become undefined?

anonymous · Answer

What do you mean?

lyrae · Answer

What's the domain of t?

anonymous · Answer

All numbers except 0?

lyrae · Answer

What happens if you try t=1?

anonymous · Answer

Sorry, so all numbers except 0 and 1?

lyrae · Answer

t=2, t=3 ...  ?

anonymous · Answer

Oh sorry. I was using the wrong standard. Forgot everything under a square root must be greater than or equal to 0. So x would be... (-infinity, 0)? Sorry if I'm not getting anywhere

lyrae · Answer

Don't worry, we're making progress :) 
so t would be -infinity <= t <= 0

lyrae · Answer

then you set t to the exponent in the problem given.

lyrae · Answer

so t = 4x + 6 gives 4x + 6 <= 0

anonymous · Answer

Ah, got it. :) (-infinity, -7/4] Thank you!!

lyrae · Answer

Awesome :) Yw