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graph this line
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|dw:1392944484549:dw|
@Lyrae
Inset some values on x, for example 3, and 6 and calculate the corresponding y-value
y-values*
so 1/3 times 3 plus 2?
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yes
so do I do the equation or do i plot a point on 3 for x and go from there?
you need two points. you plot them in the graph and draw a line between them
or would i then do the equation and that would be my y point?
so would 1/3 x 3+2 = 3 be my point for y?
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aah, ok. You need to plot two points in the graph. By selecting a x-value you can calculate it's corresponding y-value. Example: x = 3 y =1/3 x 3 + 2 = 3 gives one point in the graph: (3, 3)
so y = 3?
yes, if x=3
so it would be: |dw:1392945568594:dw|
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