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OpenStudy (timaashorty):
what is the graph of the equation ?
(x+8)^2+(y-1)^2=9?
Please show your work.
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OpenStudy (anonymous):
Looks like a circle.
OpenStudy (timaashorty):
\[(x+8)^{2} + (y-1)^{2} = 9\]
OpenStudy (timaashorty):
I know it's a circle and how it looks graphed. I just need to know before I graph it, do I need to do any work.
OpenStudy (shamil98):
(x-h)^2 + (y-k)^2 = r^2
r = 3 radius of circle
(h,k) = the center of the circle.
OpenStudy (timaashorty):
(8, 1) is the center?
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OpenStudy (shamil98):
no, (-8,1) is.
OpenStudy (timaashorty):
Oops I see. can you show me how you got the radius
OpenStudy (shamil98):
(x-h)^2 + (y-k)^2 = r^2
(x-(-8)^2 + (y-(+1)^2 = 3^2
OpenStudy (shamil98):
you have 9,
r^2 = 9
r = 3
OpenStudy (timaashorty):
Oh Okay |dw:1392956172920:dw|
just to make sure, This is how it will be graphed right?
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OpenStudy (anonymous):
That's a little sloppy, but it gets the point across. If you label some points with their coordinates it would be more convincing.
OpenStudy (shamil98):
Yes, but the radius is 3 so remember the distance between the circle's points are 3.
OpenStudy (timaashorty):
yeah i know, it's just im in a rush right now, but it's similar?
OpenStudy (timaashorty):
Thanks for the help guys
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