Question

h(x)=x^2+3x/4x+27
find h(-8)
can someone please help?!?!?!

Answer 1

so what the problem is telling you x=-8 so fill in your variables and solve

Answer 2

thank you.. would it be
-8= -8^2+3(8)/4(8)+27?

Answer 3

correct

Answer 4

to me it looks like a false answer, is that an option?

Answer 5

it says to simplify my answer is all..

Answer 6

well nvm lol just simplify

Answer 7

this is harder than I thought it'd be. I got -6.625 but it says its incorrect

Answer 8

\(f(-8)\) does NOT mean set it equal to \(-8\) and solve for \(x\)
it means replace \(x\) by \(-8\) and see what you get

Answer 9

\[h(x)=\frac{x^2+3x}{4x+27}\]\[h(-8)=\frac{(-8)^2+3\times (-8)}{4\times (-8)+27}\]