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Find the zeros of the polynomial function. f(x) = x3 - 6x2 + 9x
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factorize it..this time it's ur turn.. :) first take out a common factor.. u can take out "x" as the common factor ... wt will u get then ?
3-6(2)+9????? omg I dunno
x [ x^2 - 6x + 9 ]
now u can factorize the other parts x [ x^2 - 6x + 9 ] = x [ x^2 -3x - 3x + 9 ] = x[ x ( x -3 ) - 3( x -3 ) ] = x [ ( x-3) ( x-3) ]
ooooohhh I c I didn't put in the exponents the right way, hahaha its supposed to be x^3-6x^2+9x
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so... if the function is equal to zero x = 0 or x= 3 which means zeros r 0 and 3
yup.....ur so right! :D
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