Question

Evaluate C(n, n).



0

1

n

Answer 1

this is confusing can you explain ?

Answer 2

\[
{n\choose n}= \frac{n!}{n!(n-n)!}
\]

Answer 3

In general \[
{n\choose k} = \frac{n!}{k!(n-k)!}
\]

Answer 4

wouldnt be any of those than

Answer 5

What?

Answer 6

wouldnt the awnser be any of the multiple chioce awnsers

Answer 7

No \[
\frac{n!}{n!(n-n)!}= \frac{1}{0!}= 1
\]

Answer 8

ok