Question

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Answer 1

Try clearing the fractions by multiplying both sides by (b+1)(b-1)

Answer 2

so 1 * (b+1) and 1 * (b-1)? @myininaya

Answer 3

So (b-1)+(b+1)=2

Answer 4

the b+1 will cancel in the first fraction
the b-1 will cancel in the second fraction
in the last fraction the b^2-1 will cancel because (b-1)(b+1) is the same as b^2-1

Answer 5

Recall b^2-1=(b-1)(b+1)

Answer 6

Ahh okay. So there are no solutions?

Answer 7

@myininaya

Answer 8

there is no solution very good. you knew that because 1 isn't in the domain of the original equation right?

Answer 9

It should be (b-1)+(b+1)=2

Answer 10

Ahh okay thanks. Changed it. Anything else?

Answer 11

I think it looks fine.