Question

Need help on how to solve

Answer 1

Multiply both sides by \(x^2\). Or if you want to get rid of all fractions do \(30x^2\).

Answer 2

Just x^2?

Answer 3

Sure.

Answer 4

try it and see what happens.

Answer 5

3x^2/(2x)(x^2) + 5x^2/(6x)(x^2)=4/(5x^2)

Answer 6

still need help

Answer 7

3/(2x) +5/(6x)=4/(5x^2)

Answer 8

7/3x=4/5x^2

Answer 9

now what

Answer 10

\[\frac{ 3 }{ 2x }+\frac{ 5 }{ 6x }=\frac{ 3*3+5 }{6x }=\frac{ 14 }{ 6x }=\frac{ 7 }{3x }\]
\[\frac{ 7 }{ 3x }=\frac{ 4 }{5x^2 }\]
cross multiply ,remember x not equal to zero.

Answer 11

35x=12?

Answer 12

\[35x^2=12x\]
\[35 x^2-12x=0,x(35x-12)=0,x \neq 0,35x-12=0,x=\frac{ 12 }{ 35 }\]