Question

3(2x - 3) + 4(2 - x) = 0

1/2
17/10
-17/2

Answer 1

\[3(2x-3) + 4(2-x) = 0\]Can you use the distributive property to remove the parentheses?

Answer 2

3*2x=(3*2)x=6x
3*3=(3*-3)=-9
6x-9

4*2=(4*2)= 8
4*-x=(4*-1)x=-4x
8-4x

6x-9+4x=-4x+8+4x
10x-9=8
10x-9+9=8+9
10x=17
10x/10=17/10
x=1.7

Answer 3

Sorry, but that's incorrect...

Answer 4

lol i was eating

Answer 5

those are fractions in the end

Answer 6

i dont think you can use the distributive property for the parenthesis

Answer 7

the end is dividing both sides of the equation by 10

Answer 8

you most certainly can use the distributive property!

a(b+c) = a*b + a*c
a(b-c) = a*b - a*c

Answer 9

@ken_boy05 your mistake is in this line \[6x-9+4x=-4x+8+4x\]

Answer 10

@ChrisNeedsHelp stick to the problem we're working on, eh?

Answer 11

you need to group your variables 6x and -4x to do that you add 4x to both sides
6x-9+4x=-4x+8+4x

Answer 12

@ken_boy05 if you still think you are getting the right answer, plug it into the original equation. does it fit?

Answer 13

so whats your answer@whpalmer4?

Answer 14

I'm waiting for the original poster to do some work, I'm not going to give him the answer.

Answer 15

lol

Answer 16

@ken_boy05 he is right you made a mistake

Answer 17

Well obviously he said he is eating so he doesn't really care that much lol

Answer 18

6x -9 + 8 - 4x = 0

Answer 19

Well I grew up in England and moved here from Canada ...the British way sometimes is different ...I could be wrong but that's how I learnt

Answer 20

tricia that part yes i did not include it was b4 6x-9+4x=-4x+8+4x

Answer 21

@6x -9 + 8 - 4x = 0

Answer 22

10x-9+9=8+9
this is where you made the mistake

Answer 23

it was -9 on the right

Answer 24

there is nothing wrong with your method!!!

Answer 25

actually there's a mistake in the line I pointed out — wrong sign on the 4x

Answer 26

on the left hand side

Answer 27

4(2-x) = 8 - 4x

Answer 28

American way is not the only way ...your method i can already tell might end up in x=0.5 and its correct as well

Answer 29

Math is logic

Answer 30

Can you please help Chris? Thanks

Answer 31

Chris needs to pull on the big boy pants and do some work. I told him the first step, and will help him further when he does it.

There's no American way versus British way or Canadian way here, don't be ridiculous. Algebraic manipulation is the same no matter where you are.

Answer 32

The issue was that you changed a sign when you shouldn't have. An honest mistake, happens all the time.

Answer 33

agree Algebraic manipulation is the same no matter where you are.

Answer 34

so your argument is the manipulation is only one way ??smh ...The ancient Arabs and Egyptians that started math write and work from left to right ...plsssss...show him ur method and we already know its x=0.5

Answer 35

Good reason for checking your work before posting it :-)

Answer 36

produce a living ancient Arab or Egyptian, and I'll be happy to discuss it with them.

Answer 37

the underlying mathematics do not change just because you use Roman numerals or Babylonian notation.

Answer 38

The ancient manuscripts are still alive and healthy ...you haven't
seen one before

Answer 39

the distributive principle does not depend on the year or the lat/long

Answer 40

Just help Chris pls lol Thanks

Answer 41

Ken, you made a mistake. Don't try to blame dead people for it.

Answer 42

well you that is alive don't want to help chris

Answer 43

Chris can only be helped if he takes part.

Answer 44

3(2x-3) + 4(2-x) = 0
3*2x - 3*3 + 4*2 + 4(-x) = 0
6x - 9 + 8 - 4x = 0
6x - 1 - 4x = 0
2x - 1 = 0
2x = 1
x = 1/2 or 0.5

Answer 45

enough by the way,I learnt the "British" way and a mistake is just that

Answer 46

Chris have a great night ...that's your American answer

Answer 47

Still cant find clue to this maybe you can help
Find an equation in point -slope form for the line having the specified slope and containing the point indicated m=4, ( 3,8 )

Answer 48

@whpalmer4 and triciaal

Answer 49

@ken_boy05 please don't put new questions in someone else's question. post it as a new question and I'll be there with the answer for you.

Answer 50

i put it there before already @whpalmer4