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Mathematics 20 Online
OpenStudy (anonymous):

x^3-6x^2+2x-12

OpenStudy (anonymous):

factor by grouping then check your answer

OpenStudy (whpalmer4):

Do you have an answer yet, or do you need help factoring it?

OpenStudy (anonymous):

need nelp

OpenStudy (anonymous):

help

OpenStudy (anonymous):

x^3+6x^2-2x-12 x^3 + 6x^2 = group 1 -2x - 12 = group 2 x^3 + 6x^2 becomes x^2(x + 6) -2x - 12 becomes -2(x + 6) (x^2 - 2)(x + 6)

OpenStudy (whpalmer4):

Okay, to factor this start by writing the equation in descending order of exponents. You've that already. Then put parentheses around each pair of terms starting from the left: \[(x^3-6x^2) + (2x-12)\]Now, factor each of those grouped pairs. What do you get?

OpenStudy (anonymous):

don't know

OpenStudy (whpalmer4):

Factor \[(x^3-6x^2)\]are there any common factors?

OpenStudy (whpalmer4):

Hint:\[x^3-6x^2 = x*x*x - 6*x*x\]

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