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have a question on limits ill post question
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\[\lim x \rightarrow0^+ Sin(4\pi/3)e^\sqrt{x}\]
\[\lim_{x \rightarrow 0+}e ^{x}=1\]
\[\sin \frac{ 4\pi }{ 3 }=\sin \left( \pi+\frac{ \pi }{ 3 } \right)=-\sin \frac{ \pi }{ 3}=-\frac{ \sqrt{3} }{2 }\]
so the answer would be -sqrt3/2 then?
im really bad at these btw
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oops make that the answer is \[\sin(\frac{4\pi}{3})\] whatever that is
there is a second part also that ask if the function is continuous at x=0
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